6,033*(1+(.042x))^(25x)=x

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Solution for 6,033*(1+(.042x))^(25x)=x equation: 



6.033(1+(.042x))^(25x)=x

We move all terms to the left:

6.033(1+(.042x))^(25x)-(x)=0

We add all the numbers together, and all the variables

6.033(1+(+.042x))^25x-x=0

We add all the numbers together, and all the variables

-1x+6.033(1+(+.042x))^25x=0

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